About JEE (Main & Advance)

Admission to Undergraduate Engineering Programs at NITS, IIITS, Other centrally funded Technical Institutions, Institutions funded by several participating State Governments, and several other Institutions shall involve the Joint Entrance Examination, JEE (Main). The JEE (Main) will also be an eligibility test for the JEE (Advance), which the candidate has to take if he/she is aspiring for admission to the undergraduate programmes offered by the IITs.


1. The percentage of marks and percentile are totally different entities hence the candidates should not confuse with both the above terms.
2. Percentage is a number out of 100.
3. Percentile Score of a candidate in a Board or JEE (Main) will reflect how many Candidates have scored below that candidate in his/her Board or JEE (Main) Examination.

A Percentile score is the value below which a certain percent of observations fall. For example, the 40th Percentile is the value or score below which 40 Percent of the observations may be found. The Percentile of a Candidate will be calculated as100 x Number of candidates in the ‘group’ with aggregate marks less than the candidate Total number of the candidates in the ‘group’

The detailed formula for normalization of Qualifying examination marks is as follows :-

i. Note down the aggregate marks (A0) obtained by each student in JEE-Main.
ii. Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board  whose subject combinations meet the eligibility criteria of JEE-Main. The variable B, is only a base for calculating percentile (P), which is further used to get corresponding JEE (Main) marks.

iii. Determine the JEE Main aggregate marks – corresponding to percentile (P) at the All- India level.

Regard this as B₁.

iv. Also, determine the JEE-Main aggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE-Main by the students of that board. Regard this as B₂. The normalized board score of the candidate was computed as:

B final = 0.5 * (B1 + B2)

For the purpose of admission to CFTIS where it has been decided to use the JEE Mains performance and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit list was computed as:

C= 0.6* A0 +0.4* Bfinal

Five subjects to be used for normalization:-

1. Physics
2. Mathematics
3. Any one of the subjects Chemistry, Biology. Biotechnology and Technical Vocational subject

4. Any subject other than the above four subjects.
5. One language


In respect of 3, 4 and 5, the best mark in a given category will be chosen.


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